Base | Representation |
---|---|
bin | 101101111110110001… |
… | …010110100001000001 |
3 | 11201102210012101222012 |
4 | 231332301112201001 |
5 | 1302103101204003 |
6 | 34403030422305 |
7 | 3365320611632 |
oct | 557661264101 |
9 | 151383171865 |
10 | 49371506753 |
11 | 19a35a23848 |
12 | 969a501995 |
13 | 486a7a8c2a |
14 | 256508b889 |
15 | 143e5e98d8 |
hex | b7ec56841 |
49371506753 has 2 divisors, whose sum is σ = 49371506754. Its totient is φ = 49371506752.
The previous prime is 49371506749. The next prime is 49371506827. The reversal of 49371506753 is 35760517394.
49371506753 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49340848384 + 30658369 = 222128^2 + 5537^2 .
It is a cyclic number.
It is not a de Polignac number, because 49371506753 - 22 = 49371506749 is a prime.
It is not a weakly prime, because it can be changed into another prime (49371506713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24685753376 + 24685753377.
It is an arithmetic number, because the mean of its divisors is an integer number (24685753377).
Almost surely, 249371506753 is an apocalyptic number.
It is an amenable number.
49371506753 is a deficient number, since it is larger than the sum of its proper divisors (1).
49371506753 is an equidigital number, since it uses as much as digits as its factorization.
49371506753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2381400, while the sum is 50.
The spelling of 49371506753 in words is "forty-nine billion, three hundred seventy-one million, five hundred six thousand, seven hundred fifty-three".
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