Base | Representation |
---|---|
bin | 10110011100111110001100… |
… | …00011101011010010010011 |
3 | 20110211002211222212202020101 |
4 | 23032133012003223102103 |
5 | 22432420343302420034 |
6 | 253002031202553231 |
7 | 13254103023510025 |
oct | 1316370603532223 |
9 | 213732758782211 |
10 | 49373971920019 |
11 | 14806424a7689a |
12 | 565500b368817 |
13 | 2171c3a570016 |
14 | c299da640015 |
15 | 5a94e4c43514 |
hex | 2ce7c60eb493 |
49373971920019 has 2 divisors, whose sum is σ = 49373971920020. Its totient is φ = 49373971920018.
The previous prime is 49373971919999. The next prime is 49373971920037. The reversal of 49373971920019 is 91002917937394.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49373971920019 - 231 = 49371824436371 is a prime.
It is a super-2 number, since 2×493739719200192 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (49373971920319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24686985960009 + 24686985960010.
It is an arithmetic number, because the mean of its divisors is an integer number (24686985960010).
Almost surely, 249373971920019 is an apocalyptic number.
49373971920019 is a deficient number, since it is larger than the sum of its proper divisors (1).
49373971920019 is an equidigital number, since it uses as much as digits as its factorization.
49373971920019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23147208, while the sum is 64.
The spelling of 49373971920019 in words is "forty-nine trillion, three hundred seventy-three billion, nine hundred seventy-one million, nine hundred twenty thousand, nineteen".
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