4938071113 has 2 divisors, whose sum is σ = 4938071114. Its totient is φ = 4938071112.

The previous prime is 4938071009. The next prime is 4938071123. The reversal of 4938071113 is 3111708394.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2765392569 + 2172678544 = 52587^2 + 46612^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4938071113 is a prime.

It is not a weakly prime, because it can be changed into another prime (4938071123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2469035556 + 2469035557.

It is an arithmetic number, because the mean of its divisors is an integer number (2469035557).

Almost surely, 2^4938071113 is an apocalyptic number.

It is an amenable number.

4938071113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4938071113 is an equidigital number, since it uses as much as digits as its factorization.

4938071113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 37.

The square root of 4938071113 is about 70271.4103530020. The cubic root of 4938071113 is about 1702.8868036220.

The spelling of 4938071113 in words is "four billion, nine hundred thirty-eight million, seventy-one thousand, one hundred thirteen".