4938509793673 has 2 divisors, whose sum is σ = 4938509793674. Its totient is φ = 4938509793672.

The previous prime is 4938509793661. The next prime is 4938509793689. The reversal of 4938509793673 is 3763979058394.

4938509793673 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3792222653769 + 1146287139904 = 1947363^2 + 1070648^2 .

It is a cyclic number.

It is not a de Polignac number, because 4938509793673 - 2⁵ = 4938509793641 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4938509793596 and 4938509793605.

It is not a weakly prime, because it can be changed into another prime (4938509790673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2469254896836 + 2469254896837.

It is an arithmetic number, because the mean of its divisors is an integer number (2469254896837).

Almost surely, 2^{4938509793673} is an apocalyptic number.

It is an amenable number.

4938509793673 is a deficient number, since it is larger than the sum of its proper divisors (1).

4938509793673 is an equidigital number, since it uses as much as digits as its factorization.

4938509793673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 925888320, while the sum is 73.

The spelling of 4938509793673 in words is "four trillion, nine hundred thirty-eight billion, five hundred nine million, seven hundred ninety-three thousand, six hundred seventy-three".