4940132803 has 4 divisors (see below), whose sum is σ = 5110482240. Its totient is φ = 4769783368.

The previous prime is 4940132789. The next prime is 4940132839. The reversal of 4940132803 is 3082310494.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4940132803 is a prime.

It is a super-2 number, since 2×4940132803² = 48809824222553273618, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4940132893) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85174675 + ... + 85174732.

It is an arithmetic number, because the mean of its divisors is an integer number (1277620560).

Almost surely, 2^4940132803 is an apocalyptic number.

4940132803 is a deficient number, since it is larger than the sum of its proper divisors (170349437).

4940132803 is a wasteful number, since it uses less digits than its factorization.

4940132803 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 170349436.

The product of its (nonzero) digits is 20736, while the sum is 34.

The square root of 4940132803 is about 70286.0783014674. The cubic root of 4940132803 is about 1703.1237609364.

The spelling of 4940132803 in words is "four billion, nine hundred forty million, one hundred thirty-two thousand, eight hundred three".