494100931 has 2 divisors, whose sum is σ = 494100932. Its totient is φ = 494100930.

The previous prime is 494100913. The next prime is 494100941. The reversal of 494100931 is 139001494.

Together with previous prime (494100913) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 494100931 - 2⁵ = 494100899 is a prime.

It is a super-2 number, since 2×494100931² = 488271460030133522, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 494100893 and 494100902.

It is not a weakly prime, because it can be changed into another prime (494100911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247050465 + 247050466.

It is an arithmetic number, because the mean of its divisors is an integer number (247050466).

Almost surely, 2^494100931 is an apocalyptic number.

494100931 is a deficient number, since it is larger than the sum of its proper divisors (1).

494100931 is an equidigital number, since it uses as much as digits as its factorization.

494100931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The square root of 494100931 is about 22228.3812051170. The cubic root of 494100931 is about 790.5667732192.

The spelling of 494100931 in words is "four hundred ninety-four million, one hundred thousand, nine hundred thirty-one".