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494125003 is a prime number
BaseRepresentation
bin11101011100111…
…011111111001011
31021102210011002001
4131130323333023
52002444000003
6121010451431
715146664451
oct3534737713
91242704061
10494125003
11233a14479
12119593b77
137b4a8c78
14498a69d1
152d5a761d
hex1d73bfcb

494125003 has 2 divisors, whose sum is σ = 494125004. Its totient is φ = 494125002.

The previous prime is 494124971. The next prime is 494125007. The reversal of 494125003 is 300521494.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 494125003 - 25 = 494124971 is a prime.

It is not a weakly prime, because it can be changed into another prime (494125007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247062501 + 247062502.

It is an arithmetic number, because the mean of its divisors is an integer number (247062502).

Almost surely, 2494125003 is an apocalyptic number.

494125003 is a deficient number, since it is larger than the sum of its proper divisors (1).

494125003 is an equidigital number, since it uses as much as digits as its factorization.

494125003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

The square root of 494125003 is about 22228.9226684516. The cubic root of 494125003 is about 790.5796114966.

Adding to 494125003 its reverse (300521494), we get a palindrome (794646497).

The spelling of 494125003 in words is "four hundred ninety-four million, one hundred twenty-five thousand, three".