Base | Representation |
---|---|
bin | 1110011000101101111… |
… | …01100011000011000011 |
3 | 1202020220001211112021222 |
4 | 13030112331203003003 |
5 | 31044314424102011 |
6 | 1015025315105255 |
7 | 50466242454623 |
oct | 7142675430303 |
9 | 1666801745258 |
10 | 494306472131 |
11 | 1806a813176a |
12 | 7b9722a222b |
13 | 377c7707984 |
14 | 19cd2dd0883 |
15 | ccd0d86ddb |
hex | 7316f630c3 |
494306472131 has 2 divisors, whose sum is σ = 494306472132. Its totient is φ = 494306472130.
The previous prime is 494306472091. The next prime is 494306472169. The reversal of 494306472131 is 131274603494.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 494306472131 - 210 = 494306471107 is a prime.
It is a super-2 number, since 2×4943064721312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (494306472031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247153236065 + 247153236066.
It is an arithmetic number, because the mean of its divisors is an integer number (247153236066).
Almost surely, 2494306472131 is an apocalyptic number.
494306472131 is a deficient number, since it is larger than the sum of its proper divisors (1).
494306472131 is an equidigital number, since it uses as much as digits as its factorization.
494306472131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 435456, while the sum is 44.
The spelling of 494306472131 in words is "four hundred ninety-four billion, three hundred six million, four hundred seventy-two thousand, one hundred thirty-one".
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