Base | Representation |
---|---|
bin | 100011111101110100111… |
… | …1111101000011101011011 |
3 | 122111120002210112111100120 |
4 | 1013323221333220131123 |
5 | 1121442021332200043 |
6 | 14302502450004323 |
7 | 1020062400055251 |
oct | 107735177503533 |
9 | 18446083474316 |
10 | 4943138162523 |
11 | 1636411697450 |
12 | 67a01ab766a3 |
13 | 29b19c8344a2 |
14 | 13136b9c25d1 |
15 | 888b0754983 |
hex | 47ee9fe875b |
4943138162523 has 16 divisors (see below), whose sum is σ = 7437950841600. Its totient is φ = 2892536437280.
The previous prime is 4943138162519. The next prime is 4943138162537. The reversal of 4943138162523 is 3252618313494.
It is a cyclic number.
It is not a de Polignac number, because 4943138162523 - 22 = 4943138162519 is a prime.
It is a super-2 number, since 2×49431381625232 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4943138162503) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2582620863 + ... + 2582622776.
It is an arithmetic number, because the mean of its divisors is an integer number (464871927600).
Almost surely, 24943138162523 is an apocalyptic number.
4943138162523 is a deficient number, since it is larger than the sum of its proper divisors (2494812679077).
4943138162523 is a wasteful number, since it uses less digits than its factorization.
4943138162523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5165243682.
The product of its digits is 3732480, while the sum is 51.
The spelling of 4943138162523 in words is "four trillion, nine hundred forty-three billion, one hundred thirty-eight million, one hundred sixty-two thousand, five hundred twenty-three".
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