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4947336215281 is a prime number
BaseRepresentation
bin100011111111110010000…
…1101111011101011110001
3122111221221100220200010001
41013333210031323223301
51122024121032342111
614304435212510001
71020301413656155
oct107774415735361
918457840820101
104947336215281
111638176353639
1267a9b0a7b301
1329b6bb4aaa85
1413164936d065
1588a5909c1c1
hex47fe437baf1

4947336215281 has 2 divisors, whose sum is σ = 4947336215282. Its totient is φ = 4947336215280.

The previous prime is 4947336215257. The next prime is 4947336215287. The reversal of 4947336215281 is 1825126337494.

4947336215281 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4017683501056 + 929652714225 = 2004416^2 + 964185^2 .

It is a cyclic number.

It is not a de Polignac number, because 4947336215281 - 213 = 4947336207089 is a prime.

It is a super-2 number, since 2×49473362152812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4947336215287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2473668107640 + 2473668107641.

It is an arithmetic number, because the mean of its divisors is an integer number (2473668107641).

Almost surely, 24947336215281 is an apocalyptic number.

It is an amenable number.

4947336215281 is a deficient number, since it is larger than the sum of its proper divisors (1).

4947336215281 is an equidigital number, since it uses as much as digits as its factorization.

4947336215281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8709120, while the sum is 55.

The spelling of 4947336215281 in words is "four trillion, nine hundred forty-seven billion, three hundred thirty-six million, two hundred fifteen thousand, two hundred eighty-one".