Base | Representation |
---|---|
bin | 1110011010000110001… |
… | …11101100110110010001 |
3 | 1202022210200220001220101 |
4 | 13031003013230312101 |
5 | 31102324104044332 |
6 | 1015231022212401 |
7 | 50523506612635 |
oct | 7150307546621 |
9 | 1668720801811 |
10 | 495047331217 |
11 | 180a483490aa |
12 | 7bb3a424101 |
13 | 378b505192a |
14 | 19d63562dc5 |
15 | cd25e2aae7 |
hex | 73431ecd91 |
495047331217 has 2 divisors, whose sum is σ = 495047331218. Its totient is φ = 495047331216.
The previous prime is 495047331209. The next prime is 495047331239. The reversal of 495047331217 is 712133740594.
It is a Cunningham number, because it is equal to 7035962+1.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 495047331216 + 1 = 703596^2 + 1^2 .
It is a cyclic number.
It is not a de Polignac number, because 495047331217 - 23 = 495047331209 is a prime.
It is not a weakly prime, because it can be changed into another prime (495047331277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 247523665608 + 247523665609.
It is an arithmetic number, because the mean of its divisors is an integer number (247523665609).
Almost surely, 2495047331217 is an apocalyptic number.
It is an amenable number.
495047331217 is a deficient number, since it is larger than the sum of its proper divisors (1).
495047331217 is an equidigital number, since it uses as much as digits as its factorization.
495047331217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 635040, while the sum is 46.
The spelling of 495047331217 in words is "four hundred ninety-five billion, forty-seven million, three hundred thirty-one thousand, two hundred seventeen".
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