49514306113 has 4 divisors (see below), whose sum is σ = 50665801648. Its totient is φ = 48362810580.

The previous prime is 49514306077. The next prime is 49514306119. The reversal of 49514306113 is 31160341594.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 49514306113 - 2⁹ = 49514305601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (49514306119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 575747703 + ... + 575747788.

It is an arithmetic number, because the mean of its divisors is an integer number (12666450412).

Almost surely, 2^49514306113 is an apocalyptic number.

49514306113 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

49514306113 is a deficient number, since it is larger than the sum of its proper divisors (1151495535).

49514306113 is a wasteful number, since it uses less digits than its factorization.

49514306113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1151495534.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 49514306113 in words is "forty-nine billion, five hundred fourteen million, three hundred six thousand, one hundred thirteen".