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4957381034267 is a prime number
BaseRepresentation
bin100100000100011101011…
…1011111000000100011011
3122112220212102000100022212
41020020322323320010123
51122210204021044032
614313220040105335
71021105344346544
oct110107273700433
918486772010285
104957381034267
11164146039a832
12680934a6524b
1329c62c55b34c
14131d1d43b4cb
1588e45d5ebb2
hex4823aef811b

4957381034267 has 2 divisors, whose sum is σ = 4957381034268. Its totient is φ = 4957381034266.

The previous prime is 4957381034209. The next prime is 4957381034311. The reversal of 4957381034267 is 7624301837594.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4957381034267 - 210 = 4957381033243 is a prime.

It is not a weakly prime, because it can be changed into another prime (4957381084267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2478690517133 + 2478690517134.

It is an arithmetic number, because the mean of its divisors is an integer number (2478690517134).

It is a 2-persistent number, because it is pandigital, and so is 2⋅4957381034267 = 9914762068534, but 3⋅4957381034267 = 14872143102801 is not.

Almost surely, 24957381034267 is an apocalyptic number.

4957381034267 is a deficient number, since it is larger than the sum of its proper divisors (1).

4957381034267 is an equidigital number, since it uses as much as digits as its factorization.

4957381034267 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30481920, while the sum is 59.

The spelling of 4957381034267 in words is "four trillion, nine hundred fifty-seven billion, three hundred eighty-one million, thirty-four thousand, two hundred sixty-seven".