Base | Representation |
---|---|
bin | 100100000100011101011… |
… | …1011111000000100011011 |
3 | 122112220212102000100022212 |
4 | 1020020322323320010123 |
5 | 1122210204021044032 |
6 | 14313220040105335 |
7 | 1021105344346544 |
oct | 110107273700433 |
9 | 18486772010285 |
10 | 4957381034267 |
11 | 164146039a832 |
12 | 680934a6524b |
13 | 29c62c55b34c |
14 | 131d1d43b4cb |
15 | 88e45d5ebb2 |
hex | 4823aef811b |
4957381034267 has 2 divisors, whose sum is σ = 4957381034268. Its totient is φ = 4957381034266.
The previous prime is 4957381034209. The next prime is 4957381034311. The reversal of 4957381034267 is 7624301837594.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4957381034267 - 210 = 4957381033243 is a prime.
It is not a weakly prime, because it can be changed into another prime (4957381084267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2478690517133 + 2478690517134.
It is an arithmetic number, because the mean of its divisors is an integer number (2478690517134).
It is a 2-persistent number, because it is pandigital, and so is 2⋅4957381034267 = 9914762068534, but 3⋅4957381034267 = 14872143102801 is not.
Almost surely, 24957381034267 is an apocalyptic number.
4957381034267 is a deficient number, since it is larger than the sum of its proper divisors (1).
4957381034267 is an equidigital number, since it uses as much as digits as its factorization.
4957381034267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30481920, while the sum is 59.
The spelling of 4957381034267 in words is "four trillion, nine hundred fifty-seven billion, three hundred eighty-one million, thirty-four thousand, two hundred sixty-seven".
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