Base | Representation |
---|---|
bin | 1110011101001000000… |
… | …11000001110001000011 |
3 | 1202111000000210210210112 |
4 | 13032210003001301003 |
5 | 31114141403334011 |
6 | 1020100232421535 |
7 | 50612014026341 |
oct | 7164403016103 |
9 | 1674000723715 |
10 | 496673496131 |
11 | 18170227094a |
12 | 80312b478ab |
13 | 37ab3c18ba7 |
14 | 1a079508991 |
15 | cdbda9758b |
hex | 73a40c1c43 |
496673496131 has 8 divisors (see below), whose sum is σ = 497922769728. Its totient is φ = 495424672000.
The previous prime is 496673496127. The next prime is 496673496133. The reversal of 496673496131 is 131694376694.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 496673496131 - 22 = 496673496127 is a prime.
It is a super-2 number, since 2×4966734961312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (496673496133) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2157971 + ... + 2377011.
It is an arithmetic number, because the mean of its divisors is an integer number (62240346216).
Almost surely, 2496673496131 is an apocalyptic number.
496673496131 is a deficient number, since it is larger than the sum of its proper divisors (1249273597).
496673496131 is a wasteful number, since it uses less digits than its factorization.
496673496131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 224733.
The product of its digits is 17635968, while the sum is 59.
The spelling of 496673496131 in words is "four hundred ninety-six billion, six hundred seventy-three million, four hundred ninety-six thousand, one hundred thirty-one".
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