Base | Representation |
---|---|
bin | 11101100111111… |
… | …001111011000011 |
3 | 1021122012020000021 |
4 | 131213321323003 |
5 | 2004213001011 |
6 | 121152234311 |
7 | 15213300655 |
oct | 3547717303 |
9 | 1248166007 |
10 | 497000131 |
11 | 2355a8611 |
12 | 11a53b997 |
13 | 7bc74824 |
14 | 4a0146d5 |
15 | 2d974471 |
hex | 1d9f9ec3 |
497000131 has 2 divisors, whose sum is σ = 497000132. Its totient is φ = 497000130.
The previous prime is 497000107. The next prime is 497000159. The reversal of 497000131 is 131000794.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 497000131 - 29 = 496999619 is a prime.
It is a super-2 number, since 2×4970001312 = 494018260428034322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 497000096 and 497000105.
It is not a weakly prime, because it can be changed into another prime (497000531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248500065 + 248500066.
It is an arithmetic number, because the mean of its divisors is an integer number (248500066).
Almost surely, 2497000131 is an apocalyptic number.
497000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
497000131 is an equidigital number, since it uses as much as digits as its factorization.
497000131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 756, while the sum is 25.
The square root of 497000131 is about 22293.4997476843. The cubic root of 497000131 is about 792.1100091000.
The spelling of 497000131 in words is "four hundred ninety-seven million, one hundred thirty-one", and thus it is an aban number.
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