Base | Representation |
---|---|
bin | 1110011101101111101… |
… | …11011011101101100001 |
3 | 1202111212012110210201102 |
4 | 13032313313123231201 |
5 | 31120332014012433 |
6 | 1020153231244145 |
7 | 50623162206305 |
oct | 7166767335541 |
9 | 1674765423642 |
10 | 497006000993 |
11 | 181862a26757 |
12 | 803a6379655 |
13 | 37b37a87b28 |
14 | 1a0ab73dd05 |
15 | cddcd774e8 |
hex | 73b7ddbb61 |
497006000993 has 2 divisors, whose sum is σ = 497006000994. Its totient is φ = 497006000992.
The previous prime is 497006000971. The next prime is 497006001031. The reversal of 497006000993 is 399000600794.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 389515788544 + 107490212449 = 624112^2 + 327857^2 .
It is a cyclic number.
It is not a de Polignac number, because 497006000993 - 26 = 497006000929 is a prime.
It is not a weakly prime, because it can be changed into another prime (497006000923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248503000496 + 248503000497.
It is an arithmetic number, because the mean of its divisors is an integer number (248503000497).
Almost surely, 2497006000993 is an apocalyptic number.
It is an amenable number.
497006000993 is a deficient number, since it is larger than the sum of its proper divisors (1).
497006000993 is an equidigital number, since it uses as much as digits as its factorization.
497006000993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 367416, while the sum is 47.
The spelling of 497006000993 in words is "four hundred ninety-seven billion, six million, nine hundred ninety-three", and thus it is an aban number.
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