Base | Representation |
---|---|
bin | 100100001011010100100… |
… | …0010111101001111010011 |
3 | 122121022220010100021120121 |
4 | 1020112221002331033103 |
5 | 1122430342000123344 |
6 | 14324053551251111 |
7 | 1022136413414221 |
oct | 110265102751723 |
9 | 18538803307517 |
10 | 4972113286099 |
11 | 1647730366673 |
12 | 683766819a97 |
13 | 2a0b3978c51b |
14 | 132919c85b11 |
15 | 895093d6684 |
hex | 485a90bd3d3 |
4972113286099 has 2 divisors, whose sum is σ = 4972113286100. Its totient is φ = 4972113286098.
The previous prime is 4972113286093. The next prime is 4972113286139. The reversal of 4972113286099 is 9906823112794.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4972113286099 - 223 = 4972104897491 is a prime.
It is not a weakly prime, because it can be changed into another prime (4972113286093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2486056643049 + 2486056643050.
It is an arithmetic number, because the mean of its divisors is an integer number (2486056643050).
Almost surely, 24972113286099 is an apocalyptic number.
4972113286099 is a deficient number, since it is larger than the sum of its proper divisors (1).
4972113286099 is an equidigital number, since it uses as much as digits as its factorization.
4972113286099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11757312, while the sum is 61.
The spelling of 4972113286099 in words is "four trillion, nine hundred seventy-two billion, one hundred thirteen million, two hundred eighty-six thousand, ninety-nine".
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