Base | Representation |
---|---|
bin | 1001010000101110… |
… | …11100110100010011 |
3 | 110211112002002122011 |
4 | 10220113130310103 |
5 | 40140341001113 |
6 | 2141215323351 |
7 | 234134013325 |
oct | 45027346423 |
9 | 13745062564 |
10 | 4972203283 |
11 | 2121751a13 |
12 | b69220557 |
13 | 613178728 |
14 | 352507615 |
15 | 1e17b563d |
hex | 1285dcd13 |
4972203283 has 2 divisors, whose sum is σ = 4972203284. Its totient is φ = 4972203282.
The previous prime is 4972203251. The next prime is 4972203307. The reversal of 4972203283 is 3823022794.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4972203283 - 25 = 4972203251 is a prime.
It is not a weakly prime, because it can be changed into another prime (4972203983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2486101641 + 2486101642.
It is an arithmetic number, because the mean of its divisors is an integer number (2486101642).
Almost surely, 24972203283 is an apocalyptic number.
4972203283 is a deficient number, since it is larger than the sum of its proper divisors (1).
4972203283 is an equidigital number, since it uses as much as digits as its factorization.
4972203283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 40.
The square root of 4972203283 is about 70513.8517101427. The cubic root of 4972203283 is about 1706.8012751944.
The spelling of 4972203283 in words is "four billion, nine hundred seventy-two million, two hundred three thousand, two hundred eighty-three".
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