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49745320553 is a prime number
BaseRepresentation
bin101110010101000011…
…010101101001101001
311202101211121010002202
4232111003111221221
51303334300224203
634504102505545
73410510151035
oct562503255151
9152354533082
1049745320553
111a107a33675
1297837352b5
1348ca07c426
14259c9971c5
151462339388
hexb950d5a69

49745320553 has 2 divisors, whose sum is σ = 49745320554. Its totient is φ = 49745320552.

The previous prime is 49745320453. The next prime is 49745320571. The reversal of 49745320553 is 35502354794.

49745320553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49456422544 + 288898009 = 222388^2 + 16997^2 .

It is a cyclic number.

It is not a de Polignac number, because 49745320553 - 212 = 49745316457 is a prime.

It is a super-4 number, since 4×497453205534 (a number of 44 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 49745320498 and 49745320507.

It is not a weakly prime, because it can be changed into another prime (49745320153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24872660276 + 24872660277.

It is an arithmetic number, because the mean of its divisors is an integer number (24872660277).

Almost surely, 249745320553 is an apocalyptic number.

It is an amenable number.

49745320553 is a deficient number, since it is larger than the sum of its proper divisors (1).

49745320553 is an equidigital number, since it uses as much as digits as its factorization.

49745320553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2268000, while the sum is 47.

The spelling of 49745320553 in words is "forty-nine billion, seven hundred forty-five million, three hundred twenty thousand, five hundred fifty-three".