Base | Representation |
---|---|
bin | 1011111000101… |
… | …0011100000001 |
3 | 10110210122111111 |
4 | 2332022130001 |
5 | 100230200423 |
6 | 4540243321 |
7 | 1143501415 |
oct | 276123401 |
9 | 113718444 |
10 | 49850113 |
11 | 26159145 |
12 | 14840541 |
13 | a435111 |
14 | 6898d45 |
15 | 459a60d |
hex | 2f8a701 |
49850113 has 4 divisors (see below), whose sum is σ = 49993300. Its totient is φ = 49706928.
The previous prime is 49850111. The next prime is 49850149. The reversal of 49850113 is 31105894.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31105894 = 2 ⋅15552947.
It can be written as a sum of positive squares in 2 ways, for example, as 24920064 + 24930049 = 4992^2 + 4993^2 .
It is a cyclic number.
It is not a de Polignac number, because 49850113 - 21 = 49850111 is a prime.
It is a super-2 number, since 2×498501132 = 4970067532225538, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (49850111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71070 + ... + 71767.
It is an arithmetic number, because the mean of its divisors is an integer number (12498325).
Almost surely, 249850113 is an apocalyptic number.
49850113 is the 4993-rd centered square number.
It is an amenable number.
49850113 is a deficient number, since it is larger than the sum of its proper divisors (143187).
49850113 is a wasteful number, since it uses less digits than its factorization.
49850113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143186.
The product of its (nonzero) digits is 4320, while the sum is 31.
The square root of 49850113 is about 7060.4612455561. The cubic root of 49850113 is about 368.0346557824.
The spelling of 49850113 in words is "forty-nine million, eight hundred fifty thousand, one hundred thirteen".
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