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4990561156563 = 31663520385521
BaseRepresentation
bin100100010011111010010…
…0111111111110111010011
3122200002111210021012101020
41020213310213333313103
51123231132124002223
614340344313210523
71023361520626143
oct110476447776723
918602453235336
104990561156563
11165453773a804
12687254a00a43
132a27b97223c8
14133789d78923
1589c38c5c1e3
hex489f49ffdd3

4990561156563 has 4 divisors (see below), whose sum is σ = 6654081542088. Its totient is φ = 3327040771040.

The previous prime is 4990561156561. The next prime is 4990561156627. The reversal of 4990561156563 is 3656511650994.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4990561156563 - 21 = 4990561156561 is a prime.

It is a super-3 number, since 3×49905611565633 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4990561156497 and 4990561156506.

It is not an unprimeable number, because it can be changed into a prime (4990561156561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 831760192758 + ... + 831760192763.

It is an arithmetic number, because the mean of its divisors is an integer number (1663520385522).

Almost surely, 24990561156563 is an apocalyptic number.

4990561156563 is a deficient number, since it is larger than the sum of its proper divisors (1663520385525).

4990561156563 is a wasteful number, since it uses less digits than its factorization.

4990561156563 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1663520385524.

The product of its (nonzero) digits is 26244000, while the sum is 60.

The spelling of 4990561156563 in words is "four trillion, nine hundred ninety billion, five hundred sixty-one million, one hundred fifty-six thousand, five hundred sixty-three".

Divisors: 1 3 1663520385521 4990561156563