Base | Representation |
---|---|
bin | 111000101111100110111000… |
… | …1110010101001111111010011 |
3 | 2102110020211012101021120200001 |
4 | 1301133031301302221333103 |
5 | 1010410123134001240201 |
6 | 4525314321303110431 |
7 | 210063354530024551 |
oct | 16137156162517723 |
9 | 2373224171246601 |
10 | 499124353540051 |
11 | 1350444a4479088 |
12 | 47b91788142417 |
13 | 185672bc529515 |
14 | 8b37a6761cbd1 |
15 | 3ca858344a301 |
hex | 1c5f371ca9fd3 |
499124353540051 has 2 divisors, whose sum is σ = 499124353540052. Its totient is φ = 499124353540050.
The previous prime is 499124353540037. The next prime is 499124353540073. The reversal of 499124353540051 is 150045353421994.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 499124353540051 - 231 = 499122206056403 is a prime.
It is a super-2 number, since 2×4991243535400512 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 499124353539974 and 499124353540001.
It is not a weakly prime, because it can be changed into another prime (499124353540091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249562176770025 + 249562176770026.
It is an arithmetic number, because the mean of its divisors is an integer number (249562176770026).
Almost surely, 2499124353540051 is an apocalyptic number.
499124353540051 is a deficient number, since it is larger than the sum of its proper divisors (1).
499124353540051 is an equidigital number, since it uses as much as digits as its factorization.
499124353540051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664000, while the sum is 55.
The spelling of 499124353540051 in words is "four hundred ninety-nine trillion, one hundred twenty-four billion, three hundred fifty-three million, five hundred forty thousand, fifty-one".
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