Base | Representation |
---|---|
bin | 1110100010001111110… |
… | …11100011011010011001 |
3 | 1202202002122111002100012 |
4 | 13101013323203122121 |
5 | 31140304242001332 |
6 | 1021233132051305 |
7 | 51040111313261 |
oct | 7210773433231 |
9 | 1682078432305 |
10 | 499423000217 |
11 | 182893299a79 |
12 | 8095b903b35 |
13 | 3813174609b |
14 | 1a25a7467a1 |
15 | ced015a3b2 |
hex | 7447ee3699 |
499423000217 has 2 divisors, whose sum is σ = 499423000218. Its totient is φ = 499423000216.
The previous prime is 499423000213. The next prime is 499423000309. The reversal of 499423000217 is 712000324994.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 489634668121 + 9788332096 = 699739^2 + 98936^2 .
It is a cyclic number.
It is not a de Polignac number, because 499423000217 - 22 = 499423000213 is a prime.
It is not a weakly prime, because it can be changed into another prime (499423000213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249711500108 + 249711500109.
It is an arithmetic number, because the mean of its divisors is an integer number (249711500109).
Almost surely, 2499423000217 is an apocalyptic number.
It is an amenable number.
499423000217 is a deficient number, since it is larger than the sum of its proper divisors (1).
499423000217 is an equidigital number, since it uses as much as digits as its factorization.
499423000217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108864, while the sum is 41.
The spelling of 499423000217 in words is "four hundred ninety-nine billion, four hundred twenty-three million, two hundred seventeen", and thus it is an aban number.
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