Base | Representation |
---|---|
bin | 10110101110111000001001… |
… | …11001011110100011010001 |
3 | 20112222220212202100101202221 |
4 | 23113130010321132203101 |
5 | 23023010343333044403 |
6 | 254152420251541041 |
7 | 13346413065446212 |
oct | 1327340471364321 |
9 | 215886782311687 |
10 | 49989206534353 |
11 | 14a23337966649 |
12 | 57342b015a781 |
13 | 21b7c6752cc08 |
14 | c4b6c1d3b409 |
15 | 5ba5022badbd |
hex | 2d7704e5e8d1 |
49989206534353 has 2 divisors, whose sum is σ = 49989206534354. Its totient is φ = 49989206534352.
The previous prime is 49989206534347. The next prime is 49989206534419. The reversal of 49989206534353 is 35343560298994.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44004808166544 + 5984398367809 = 6633612^2 + 2446303^2 .
It is a cyclic number.
It is not a de Polignac number, because 49989206534353 - 29 = 49989206533841 is a prime.
It is not a weakly prime, because it can be changed into another prime (49989206534053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24994603267176 + 24994603267177.
It is an arithmetic number, because the mean of its divisors is an integer number (24994603267177).
Almost surely, 249989206534353 is an apocalyptic number.
It is an amenable number.
49989206534353 is a deficient number, since it is larger than the sum of its proper divisors (1).
49989206534353 is an equidigital number, since it uses as much as digits as its factorization.
49989206534353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 755827200, while the sum is 70.
The spelling of 49989206534353 in words is "forty-nine trillion, nine hundred eighty-nine billion, two hundred six million, five hundred thirty-four thousand, three hundred fifty-three".
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