Base | Representation |
---|---|
bin | 1110100011010011110… |
… | …11100001010101101011 |
3 | 1202210120101211021011012 |
4 | 13101221323201111223 |
5 | 31142441303321232 |
6 | 1021405510054135 |
7 | 51060205631204 |
oct | 7215173412553 |
9 | 1683511737135 |
10 | 499993417067 |
11 | 183056281661 |
12 | 80a9a94a34b |
13 | 381c2984651 |
14 | 1a2b23cc5ab |
15 | d0152829b2 |
hex | 7469ee156b |
499993417067 has 2 divisors, whose sum is σ = 499993417068. Its totient is φ = 499993417066.
The previous prime is 499993417051. The next prime is 499993417087. The reversal of 499993417067 is 760714399994.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 499993417067 - 24 = 499993417051 is a prime.
It is a super-2 number, since 2×4999934170672 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 499993416988 and 499993417006.
It is not a weakly prime, because it can be changed into another prime (499993417087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249996708533 + 249996708534.
It is an arithmetic number, because the mean of its divisors is an integer number (249996708534).
Almost surely, 2499993417067 is an apocalyptic number.
499993417067 is a deficient number, since it is larger than the sum of its proper divisors (1).
499993417067 is an equidigital number, since it uses as much as digits as its factorization.
499993417067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 92588832, while the sum is 68.
The spelling of 499993417067 in words is "four hundred ninety-nine billion, nine hundred ninety-three million, four hundred seventeen thousand, sixty-seven".
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