Base | Representation |
---|---|
bin | 1110100011010100100… |
… | …10100111010001111001 |
3 | 1202210120211012211012022 |
4 | 13101222102213101321 |
5 | 31142444331030323 |
6 | 1021410243524225 |
7 | 51060311243261 |
oct | 7215222472171 |
9 | 1683524184168 |
10 | 499999470713 |
11 | 183059736876 |
12 | 80aa0989675 |
13 | 381c3cc3ba2 |
14 | 1a2b31267a1 |
15 | d015a7b4c8 |
hex | 746a4a7479 |
499999470713 has 2 divisors, whose sum is σ = 499999470714. Its totient is φ = 499999470712.
The previous prime is 499999470671. The next prime is 499999470781. The reversal of 499999470713 is 317074999994.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 430444902889 + 69554567824 = 656083^2 + 263732^2 .
It is a cyclic number.
It is not a de Polignac number, because 499999470713 - 232 = 495704503417 is a prime.
It is not a weakly prime, because it can be changed into another prime (499999470793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249999735356 + 249999735357.
It is an arithmetic number, because the mean of its divisors is an integer number (249999735357).
Almost surely, 2499999470713 is an apocalyptic number.
It is an amenable number.
499999470713 is a deficient number, since it is larger than the sum of its proper divisors (1).
499999470713 is an equidigital number, since it uses as much as digits as its factorization.
499999470713 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138883248, while the sum is 71.
The spelling of 499999470713 in words is "four hundred ninety-nine billion, nine hundred ninety-nine million, four hundred seventy thousand, seven hundred thirteen".
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