Base | Representation |
---|---|
bin | 1110100011010100101… |
… | …00101010111011101011 |
3 | 1202210120212020012220112 |
4 | 13101222110222323223 |
5 | 31143000000304323 |
6 | 1021410303244535 |
7 | 51060315650366 |
oct | 7215224527353 |
9 | 1683525205815 |
10 | 500000009963 |
11 | 183059a74a33 |
12 | 80aa0ba974b |
13 | 381c415247c |
14 | 1a2b32270dd |
15 | d015b36178 |
hex | 746a52aeeb |
500000009963 has 2 divisors, whose sum is σ = 500000009964. Its totient is φ = 500000009962.
The previous prime is 500000009959. The next prime is 500000010001. The reversal of 500000009963 is 369900000005.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 500000009963 - 22 = 500000009959 is a prime.
It is a super-2 number, since 2×5000000099632 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (500000009263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250000004981 + 250000004982.
It is an arithmetic number, because the mean of its divisors is an integer number (250000004982).
Almost surely, 2500000009963 is an apocalyptic number.
500000009963 is a deficient number, since it is larger than the sum of its proper divisors (1).
500000009963 is an equidigital number, since it uses as much as digits as its factorization.
500000009963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7290, while the sum is 32.
Adding to 500000009963 its reverse (369900000005), we get a palindrome (869900009968).
The spelling of 500000009963 in words is "five hundred billion, nine thousand, nine hundred sixty-three".
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