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500000009963 is a prime number
BaseRepresentation
bin1110100011010100101…
…00101010111011101011
31202210120212020012220112
413101222110222323223
531143000000304323
61021410303244535
751060315650366
oct7215224527353
91683525205815
10500000009963
11183059a74a33
1280aa0ba974b
13381c415247c
141a2b32270dd
15d015b36178
hex746a52aeeb

500000009963 has 2 divisors, whose sum is σ = 500000009964. Its totient is φ = 500000009962.

The previous prime is 500000009959. The next prime is 500000010001. The reversal of 500000009963 is 369900000005.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 500000009963 - 22 = 500000009959 is a prime.

It is a super-2 number, since 2×5000000099632 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (500000009263) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250000004981 + 250000004982.

It is an arithmetic number, because the mean of its divisors is an integer number (250000004982).

Almost surely, 2500000009963 is an apocalyptic number.

500000009963 is a deficient number, since it is larger than the sum of its proper divisors (1).

500000009963 is an equidigital number, since it uses as much as digits as its factorization.

500000009963 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7290, while the sum is 32.

Adding to 500000009963 its reverse (369900000005), we get a palindrome (869900009968).

The spelling of 500000009963 in words is "five hundred billion, nine thousand, nine hundred sixty-three".