Base | Representation |
---|---|
bin | 100100011000100010100… |
… | …1101010100000101100001 |
3 | 122201001011122200202002122 |
4 | 1020301011031110011201 |
5 | 1123412012240104333 |
6 | 14345111022354025 |
7 | 1024163061423011 |
oct | 110610515240541 |
9 | 18631148622078 |
10 | 5000503050593 |
11 | 1658779677956 |
12 | 68916a42b915 |
13 | 2a3712376a3b |
14 | 1340504d3c41 |
15 | 8a11b98d798 |
hex | 48c45354161 |
5000503050593 has 2 divisors, whose sum is σ = 5000503050594. Its totient is φ = 5000503050592.
The previous prime is 5000503050497. The next prime is 5000503050611. The reversal of 5000503050593 is 3950503050005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4662887434384 + 337615616209 = 2159372^2 + 581047^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5000503050593 is a prime.
It is not a weakly prime, because it can be changed into another prime (5000503070593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2500251525296 + 2500251525297.
It is an arithmetic number, because the mean of its divisors is an integer number (2500251525297).
Almost surely, 25000503050593 is an apocalyptic number.
It is an amenable number.
5000503050593 is a deficient number, since it is larger than the sum of its proper divisors (1).
5000503050593 is an equidigital number, since it uses as much as digits as its factorization.
5000503050593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50625, while the sum is 35.
The spelling of 5000503050593 in words is "five trillion, five hundred three million, fifty thousand, five hundred ninety-three".
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