Base | Representation |
---|---|
bin | 101110100100100010… |
… | …000110011001101001 |
3 | 11210001221022101000222 |
4 | 232210202012121221 |
5 | 1304402242332133 |
6 | 34545541335425 |
7 | 3420112564526 |
oct | 564442063151 |
9 | 153057271028 |
10 | 50005042793 |
11 | 1a2305a7852 |
12 | 9836707575 |
13 | 493bb17124 |
14 | 25c528414d |
15 | 147a03de98 |
hex | ba4886669 |
50005042793 has 2 divisors, whose sum is σ = 50005042794. Its totient is φ = 50005042792.
The previous prime is 50005042771. The next prime is 50005042817. The reversal of 50005042793 is 39724050005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48449292544 + 1555750249 = 220112^2 + 39443^2 .
It is a cyclic number.
It is not a de Polignac number, because 50005042793 - 26 = 50005042729 is a prime.
It is a super-2 number, since 2×500050427932 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50005042193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25002521396 + 25002521397.
It is an arithmetic number, because the mean of its divisors is an integer number (25002521397).
Almost surely, 250005042793 is an apocalyptic number.
It is an amenable number.
50005042793 is a deficient number, since it is larger than the sum of its proper divisors (1).
50005042793 is an equidigital number, since it uses as much as digits as its factorization.
50005042793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37800, while the sum is 35.
Adding to 50005042793 its reverse (39724050005), we get a palindrome (89729092798).
The spelling of 50005042793 in words is "fifty billion, five million, forty-two thousand, seven hundred ninety-three".
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