Base | Representation |
---|---|
bin | 101110100100111001… |
… | …101101101011101001 |
3 | 11210002100221212101221 |
4 | 232210321231223221 |
5 | 1304410333424001 |
6 | 34550322142041 |
7 | 3420216316012 |
oct | 564471555351 |
9 | 153070855357 |
10 | 50011233001 |
11 | 1a234045624 |
12 | 98387b1921 |
13 | 49401a3882 |
14 | 25c6016009 |
15 | 147a8631a1 |
hex | ba4e6dae9 |
50011233001 has 4 divisors (see below), whose sum is σ = 50011938900. Its totient is φ = 50010527104.
The previous prime is 50011232969. The next prime is 50011233031. The reversal of 50011233001 is 10033211005.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5246829225 + 44764403776 = 72435^2 + 211576^2 .
It is a cyclic number.
It is not a de Polignac number, because 50011233001 - 25 = 50011232969 is a prime.
It is a super-2 number, since 2×500112330012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50011233031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233116 + ... + 392893.
It is an arithmetic number, because the mean of its divisors is an integer number (12502984725).
Almost surely, 250011233001 is an apocalyptic number.
It is an amenable number.
50011233001 is a deficient number, since it is larger than the sum of its proper divisors (705899).
50011233001 is an equidigital number, since it uses as much as digits as its factorization.
50011233001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 705898.
The product of its (nonzero) digits is 90, while the sum is 16.
Adding to 50011233001 its reverse (10033211005), we get a palindrome (60044444006).
The spelling of 50011233001 in words is "fifty billion, eleven million, two hundred thirty-three thousand, one".
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