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50012211551321 is a prime number
BaseRepresentation
bin10110101111100011000000…
…00110101001110001011001
320120002010021000100100100102
423113301200012221301121
523023400002124120241
6254211143125145145
713351156140042425
oct1327614006516131
9216063230310312
1050012211551321
1114a32072672368
12573885055b1b5
1321ba1926577a6
14c4c865373b85
155badebc6c39b
hex2d7c601a9c59

50012211551321 has 2 divisors, whose sum is σ = 50012211551322. Its totient is φ = 50012211551320.

The previous prime is 50012211551213. The next prime is 50012211551333. The reversal of 50012211551321 is 12315511221005.

Together with previous prime (50012211551213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 42074215223296 + 7937996328025 = 6486464^2 + 2817445^2 .

It is a cyclic number.

It is not a de Polignac number, because 50012211551321 - 210 = 50012211550297 is a prime.

It is not a weakly prime, because it can be changed into another prime (50012211511321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25006105775660 + 25006105775661.

It is an arithmetic number, because the mean of its divisors is an integer number (25006105775661).

Almost surely, 250012211551321 is an apocalyptic number.

It is an amenable number.

50012211551321 is a deficient number, since it is larger than the sum of its proper divisors (1).

50012211551321 is an equidigital number, since it uses as much as digits as its factorization.

50012211551321 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3000, while the sum is 29.

Adding to 50012211551321 its reverse (12315511221005), we get a palindrome (62327722772326).

The spelling of 50012211551321 in words is "fifty trillion, twelve billion, two hundred eleven million, five hundred fifty-one thousand, three hundred twenty-one".