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50013344401 = 223224275087
BaseRepresentation
bin101110100101000001…
…110001001010010001
311210002111221010200221
4232211001301022101
51304411404010101
634550435313041
73420243261466
oct564501611221
9153074833627
1050013344401
111a235257989
12983944b781
134940762917
1425c640566d
15147ab2daa1
hexba5071291

50013344401 has 4 divisors (see below), whose sum is σ = 50237619712. Its totient is φ = 49789069092.

The previous prime is 50013344389. The next prime is 50013344413. The reversal of 50013344401 is 10444331005.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (50013344389) and next prime (50013344413).

It is a cyclic number.

It is not a de Polignac number, because 50013344401 - 25 = 50013344369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50013344431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112137321 + ... + 112137766.

It is an arithmetic number, because the mean of its divisors is an integer number (12559404928).

Almost surely, 250013344401 is an apocalyptic number.

It is an amenable number.

50013344401 is a deficient number, since it is larger than the sum of its proper divisors (224275311).

50013344401 is a wasteful number, since it uses less digits than its factorization.

50013344401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 224275310.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 50013344401 its reverse (10444331005), we get a palindrome (60457675406).

The spelling of 50013344401 in words is "fifty billion, thirteen million, three hundred forty-four thousand, four hundred one".

Divisors: 1 223 224275087 50013344401