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50020153 = 253119763
BaseRepresentation
bin1011111011001…
…1111100111001
310111010021202021
42332303330321
5100301121103
64544034441
71145110231
oct276637471
9114107667
1050020153
1126264977
1214902a21
13a494631
146900cc1
1545d0bbd
hex2fb3f39

50020153 has 4 divisors (see below), whose sum is σ = 50042448. Its totient is φ = 49997860.

The previous prime is 50020151. The next prime is 50020163. The reversal of 50020153 is 35102005.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50020153 - 21 = 50020151 is a prime.

It is a super-2 number, since 2×500201532 = 5004031412286818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50020151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7351 + ... + 12412.

It is an arithmetic number, because the mean of its divisors is an integer number (12510612).

Almost surely, 250020153 is an apocalyptic number.

It is an amenable number.

50020153 is a deficient number, since it is larger than the sum of its proper divisors (22295).

50020153 is a wasteful number, since it uses less digits than its factorization.

50020153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22294.

The product of its (nonzero) digits is 150, while the sum is 16.

The square root of 50020153 is about 7072.4927005972. The cubic root of 50020153 is about 368.4526394067.

Adding to 50020153 its reverse (35102005), we get a palindrome (85122158).

The spelling of 50020153 in words is "fifty million, twenty thousand, one hundred fifty-three".

Divisors: 1 2531 19763 50020153