Base | Representation |
---|---|
bin | 10110110000000110100110… |
… | …01111100101010010000011 |
3 | 20120010221120221011201002111 |
4 | 23120003103033211102003 |
5 | 23024203122211010001 |
6 | 254224023401000151 |
7 | 13352433553631464 |
oct | 1330032317452203 |
9 | 216127527151074 |
10 | 50031323141251 |
11 | 14a3a18a665791 |
12 | 57404a4a83057 |
13 | 21bbc19c6619a |
14 | c4d759678d6b |
15 | 5bb6699ea851 |
hex | 2d80d33e5483 |
50031323141251 has 4 divisors (see below), whose sum is σ = 50157346625632. Its totient is φ = 49905299656872.
The previous prime is 50031323141201. The next prime is 50031323141279. The reversal of 50031323141251 is 15214132313005.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50031323141251 - 233 = 50022733206659 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50031323141201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63011741595 + ... + 63011742388.
It is an arithmetic number, because the mean of its divisors is an integer number (12539336656408).
Almost surely, 250031323141251 is an apocalyptic number.
50031323141251 is a deficient number, since it is larger than the sum of its proper divisors (126023484381).
50031323141251 is a wasteful number, since it uses less digits than its factorization.
50031323141251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126023484380.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 50031323141251 its reverse (15214132313005), we get a palindrome (65245455454256).
The spelling of 50031323141251 in words is "fifty trillion, thirty-one billion, three hundred twenty-three million, one hundred forty-one thousand, two hundred fifty-one".
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