Base | Representation |
---|---|
bin | 10110110000001011110101… |
… | …10011110001001110000111 |
3 | 20120011012211212002120211210 |
4 | 23120011322303301032013 |
5 | 23024224401403004112 |
6 | 254225210344302503 |
7 | 13352563331263452 |
oct | 1330057263611607 |
9 | 216135755076753 |
10 | 50034134422407 |
11 | 14a403a2548943 |
12 | 5740b4a471a33 |
13 | 21bc277513165 |
14 | c4d944b98499 |
15 | 5bb781712b3c |
hex | 2d817acf1387 |
50034134422407 has 16 divisors (see below), whose sum is σ = 69248137119840. Its totient is φ = 32095961933952.
The previous prime is 50034134422399. The next prime is 50034134422411. The reversal of 50034134422407 is 70422443143005.
It is not a de Polignac number, because 50034134422407 - 23 = 50034134422399 is a prime.
It is a super-3 number, since 3×500341344224073 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50034134422807) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 981382348 + ... + 981433329.
It is an arithmetic number, because the mean of its divisors is an integer number (4328008569990).
Almost surely, 250034134422407 is an apocalyptic number.
50034134422407 is a deficient number, since it is larger than the sum of its proper divisors (19214002697433).
50034134422407 is a wasteful number, since it uses less digits than its factorization.
50034134422407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1962816002.
The product of its (nonzero) digits is 322560, while the sum is 39.
The spelling of 50034134422407 in words is "fifty trillion, thirty-four billion, one hundred thirty-four million, four hundred twenty-two thousand, four hundred seven".
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