Base | Representation |
---|---|
bin | 101110100110010110… |
… | …010010110000110011 |
3 | 11210011001121212101121 |
4 | 232212112102300303 |
5 | 1304433042032011 |
6 | 34552550243111 |
7 | 3420632515336 |
oct | 564626226063 |
9 | 153131555347 |
10 | 50035502131 |
11 | 1a24681135a |
12 | 9844956497 |
13 | 49452201c4 |
14 | 25c933261d |
15 | 147ca58e71 |
hex | ba6592c33 |
50035502131 has 2 divisors, whose sum is σ = 50035502132. Its totient is φ = 50035502130.
The previous prime is 50035502107. The next prime is 50035502137. The reversal of 50035502131 is 13120553005.
50035502131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50035502131 - 223 = 50027113523 is a prime.
It is a super-2 number, since 2×500355021312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50035502096 and 50035502105.
It is not a weakly prime, because it can be changed into another prime (50035502137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25017751065 + 25017751066.
It is an arithmetic number, because the mean of its divisors is an integer number (25017751066).
Almost surely, 250035502131 is an apocalyptic number.
50035502131 is a deficient number, since it is larger than the sum of its proper divisors (1).
50035502131 is an equidigital number, since it uses as much as digits as its factorization.
50035502131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2250, while the sum is 25.
The spelling of 50035502131 in words is "fifty billion, thirty-five million, five hundred two thousand, one hundred thirty-one".
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