Base | Representation |
---|---|
bin | 10110110000010111101101… |
… | …10110001111001001100001 |
3 | 20120011211022012122101101211 |
4 | 23120023312312033021201 |
5 | 23024330431131130421 |
6 | 254232143152030121 |
7 | 13353210332300521 |
oct | 1330136666171141 |
9 | 216154265571354 |
10 | 50040510411361 |
11 | 14a430746347a8 |
12 | 5742229832341 |
13 | 21bca524644a2 |
14 | c4dd8b8bb681 |
15 | 5bba063699e1 |
hex | 2d82f6d8f261 |
50040510411361 has 2 divisors, whose sum is σ = 50040510411362. Its totient is φ = 50040510411360.
The previous prime is 50040510411341. The next prime is 50040510411373. The reversal of 50040510411361 is 16311401504005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49087973450961 + 952536960400 = 7006281^2 + 975980^2 .
It is a cyclic number.
It is not a de Polignac number, because 50040510411361 - 25 = 50040510411329 is a prime.
It is not a weakly prime, because it can be changed into another prime (50040510411341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25020255205680 + 25020255205681.
It is an arithmetic number, because the mean of its divisors is an integer number (25020255205681).
Almost surely, 250040510411361 is an apocalyptic number.
It is an amenable number.
50040510411361 is a deficient number, since it is larger than the sum of its proper divisors (1).
50040510411361 is an equidigital number, since it uses as much as digits as its factorization.
50040510411361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 50040510411361 its reverse (16311401504005), we get a palindrome (66351911915366).
The spelling of 50040510411361 in words is "fifty trillion, forty billion, five hundred ten million, four hundred eleven thousand, three hundred sixty-one".
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