Base | Representation |
---|---|
bin | 101110100110101011… |
… | …011001010110110001 |
3 | 11210011110000220220121 |
4 | 232212223121112301 |
5 | 1304441001043121 |
6 | 34553305010241 |
7 | 3421030525606 |
oct | 564653312661 |
9 | 153143026817 |
10 | 50041034161 |
11 | 1a24994a688 |
12 | 9846783981 |
13 | 49464091b1 |
14 | 25c9d726ad |
15 | 147d29d141 |
hex | ba6ad95b1 |
50041034161 has 2 divisors, whose sum is σ = 50041034162. Its totient is φ = 50041034160.
The previous prime is 50041034143. The next prime is 50041034167. The reversal of 50041034161 is 16143014005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34084544400 + 15956489761 = 184620^2 + 126319^2 .
It is a cyclic number.
It is not a de Polignac number, because 50041034161 - 221 = 50038937009 is a prime.
It is not a weakly prime, because it can be changed into another prime (50041034167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25020517080 + 25020517081.
It is an arithmetic number, because the mean of its divisors is an integer number (25020517081).
Almost surely, 250041034161 is an apocalyptic number.
It is an amenable number.
50041034161 is a deficient number, since it is larger than the sum of its proper divisors (1).
50041034161 is an equidigital number, since it uses as much as digits as its factorization.
50041034161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 50041034161 its reverse (16143014005), we get a palindrome (66184048166).
The spelling of 50041034161 in words is "fifty billion, forty-one million, thirty-four thousand, one hundred sixty-one".
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