50041113 has 4 divisors (see below), whose sum is σ = 66721488. Its totient is φ = 33360740.

The previous prime is 50041111. The next prime is 50041139. The reversal of 50041113 is 31114005.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 50041113 - 2¹ = 50041111 is a prime.

It is a super-3 number, since 3×50041113³ (a number of 24 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 50041092 and 50041101.

It is not an unprimeable number, because it can be changed into a prime (50041111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8340183 + ... + 8340188.

It is an arithmetic number, because the mean of its divisors is an integer number (16680372).

Almost surely, 2^50041113 is an apocalyptic number.

It is an amenable number.

50041113 is a deficient number, since it is larger than the sum of its proper divisors (16680375).

50041113 is a wasteful number, since it uses less digits than its factorization.

50041113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16680374.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 50041113 is about 7073.9743426167. The cubic root of 50041113 is about 368.5040965923.

Adding to 50041113 its reverse (31114005), we get a palindrome (81155118).

The spelling of 50041113 in words is "fifty million, forty-one thousand, one hundred thirteen".