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50042123273 is a prime number
BaseRepresentation
bin101110100110101111…
…100011010000001001
311210011112002020220002
4232212233203100021
51304441240421043
634553344212345
73421043013062
oct564657432011
9153145066802
1050042123273
111a24a52397a
12984700a0b5
1349466cab3c
1425ca177569
15147d415bb8
hexba6be3409

50042123273 has 2 divisors, whose sum is σ = 50042123274. Its totient is φ = 50042123272.

The previous prime is 50042123251. The next prime is 50042123359. The reversal of 50042123273 is 37232124005.

50042123273 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49966555024 + 75568249 = 223532^2 + 8693^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50042123273 is a prime.

It is a super-3 number, since 3×500421232733 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (50042123473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25021061636 + 25021061637.

It is an arithmetic number, because the mean of its divisors is an integer number (25021061637).

Almost surely, 250042123273 is an apocalyptic number.

It is an amenable number.

50042123273 is a deficient number, since it is larger than the sum of its proper divisors (1).

50042123273 is an equidigital number, since it uses as much as digits as its factorization.

50042123273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 29.

Adding to 50042123273 its reverse (37232124005), we get a palindrome (87274247278).

The spelling of 50042123273 in words is "fifty billion, forty-two million, one hundred twenty-three thousand, two hundred seventy-three".