Search a number
-
+
500430455201 is a prime number
BaseRepresentation
bin1110100100000111111…
…10101100000110100001
31202211200212012002202202
413102003332230012201
531144340144031301
61021521121222545
751104063453645
oct7220376540641
91684625162682
10500430455201
1118325aa448a6
1280ba1191a55
13382623935b1
141a314474c25
15d03d81066b
hex7483fac1a1

500430455201 has 2 divisors, whose sum is σ = 500430455202. Its totient is φ = 500430455200.

The previous prime is 500430455159. The next prime is 500430455221. The reversal of 500430455201 is 102554034005.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 449870684176 + 50559771025 = 670724^2 + 224855^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-500430455201 is a prime.

It is not a weakly prime, because it can be changed into another prime (500430455221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250215227600 + 250215227601.

It is an arithmetic number, because the mean of its divisors is an integer number (250215227601).

Almost surely, 2500430455201 is an apocalyptic number.

It is an amenable number.

500430455201 is a deficient number, since it is larger than the sum of its proper divisors (1).

500430455201 is an equidigital number, since it uses as much as digits as its factorization.

500430455201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 29.

Adding to 500430455201 its reverse (102554034005), we get a palindrome (602984489206).

It can be divided in two parts, 5004304 and 55201, that added together give a palindrome (5059505).

The spelling of 500430455201 in words is "five hundred billion, four hundred thirty million, four hundred fifty-five thousand, two hundred one".