Base | Representation |
---|---|
bin | 11101110101010… |
… | …000011010010001 |
3 | 1021212210001002020 |
4 | 131311100122101 |
5 | 2011112000423 |
6 | 121355242053 |
7 | 15255116001 |
oct | 3565203221 |
9 | 1255701066 |
10 | 500500113 |
11 | 237579163 |
12 | 11b749329 |
13 | 7c8cb919 |
14 | 4a686001 |
15 | 2de164e3 |
hex | 1dd50691 |
500500113 has 4 divisors (see below), whose sum is σ = 667333488. Its totient is φ = 333666740.
The previous prime is 500500081. The next prime is 500500123. The reversal of 500500113 is 311005005.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 500500113 - 25 = 500500081 is a prime.
It is a super-2 number, since 2×5005001132 = 501000726226025538, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 500500092 and 500500101.
It is not an unprimeable number, because it can be changed into a prime (500500123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83416683 + ... + 83416688.
It is an arithmetic number, because the mean of its divisors is an integer number (166833372).
Almost surely, 2500500113 is an apocalyptic number.
It is an amenable number.
500500113 is a deficient number, since it is larger than the sum of its proper divisors (166833375).
500500113 is a wasteful number, since it uses less digits than its factorization.
500500113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166833374.
The product of its (nonzero) digits is 75, while the sum is 15.
The square root of 500500113 is about 22371.8598466913. The cubic root of 500500113 is about 793.9650644384.
Adding to 500500113 its reverse (311005005), we get a palindrome (811505118).
The spelling of 500500113 in words is "five hundred million, five hundred thousand, one hundred thirteen".
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