Base | Representation |
---|---|
bin | 101110100111011001… |
… | …010000000000010001 |
3 | 11210012021122121200122 |
4 | 232213121100000101 |
5 | 1310002040220411 |
6 | 34554414400025 |
7 | 3421234641353 |
oct | 564731200021 |
9 | 153167577618 |
10 | 50053054481 |
11 | 1a25570a731 |
12 | 984a800015 |
13 | 4948a57501 |
14 | 25cb7c10d3 |
15 | 147e3749db |
hex | ba7650011 |
50053054481 has 2 divisors, whose sum is σ = 50053054482. Its totient is φ = 50053054480.
The previous prime is 50053054477. The next prime is 50053054517. The reversal of 50053054481 is 18445035005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42021310081 + 8031744400 = 204991^2 + 89620^2 .
It is a cyclic number.
It is not a de Polignac number, because 50053054481 - 22 = 50053054477 is a prime.
It is a super-3 number, since 3×500530544813 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (50053054781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25026527240 + 25026527241.
It is an arithmetic number, because the mean of its divisors is an integer number (25026527241).
Almost surely, 250053054481 is an apocalyptic number.
It is an amenable number.
50053054481 is a deficient number, since it is larger than the sum of its proper divisors (1).
50053054481 is an equidigital number, since it uses as much as digits as its factorization.
50053054481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48000, while the sum is 35.
Adding to 50053054481 its reverse (18445035005), we get a palindrome (68498089486).
The spelling of 50053054481 in words is "fifty billion, fifty-three million, fifty-four thousand, four hundred eighty-one".
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