Base | Representation |
---|---|
bin | 100100011010110111100… |
… | …0011001010011100110011 |
3 | 122201112001220100002002210 |
4 | 1020311233003022130303 |
5 | 1124002231000000201 |
6 | 14351254524343203 |
7 | 1024430645663535 |
oct | 110655703123463 |
9 | 18645056302083 |
10 | 5005500000051 |
11 | 165a903290a51 |
12 | 68a1239a4b03 |
13 | 2a402a6a7c75 |
14 | 1343a5ddd855 |
15 | 8a3104e11d6 |
hex | 48d6f0ca733 |
5005500000051 has 4 divisors (see below), whose sum is σ = 6674000000072. Its totient is φ = 3337000000032.
The previous prime is 5005500000019. The next prime is 5005500000077. The reversal of 5005500000051 is 1500000055005.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5005500000051 - 25 = 5005500000019 is a prime.
It is a super-2 number, since 2×50055000000512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5005499999973 and 5005500000027.
It is not an unprimeable number, because it can be changed into a prime (5005500000451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 834250000006 + ... + 834250000011.
It is an arithmetic number, because the mean of its divisors is an integer number (1668500000018).
Almost surely, 25005500000051 is an apocalyptic number.
5005500000051 is a deficient number, since it is larger than the sum of its proper divisors (1668500000021).
5005500000051 is a wasteful number, since it uses less digits than its factorization.
5005500000051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1668500000020.
The product of its (nonzero) digits is 625, while the sum is 21.
Adding to 5005500000051 its reverse (1500000055005), we get a palindrome (6505500055056).
The spelling of 5005500000051 in words is "five trillion, five billion, five hundred million, fifty-one", and thus it is an aban number.
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