Base | Representation |
---|---|
bin | 10110110000110011101110… |
… | …10001101101110101111011 |
3 | 20120020021010100021200012001 |
4 | 23120121313101231311323 |
5 | 23030102231300004012 |
6 | 254243111402401431 |
7 | 13354252122554302 |
oct | 1330316721556573 |
9 | 216207110250161 |
10 | 50055550000507 |
11 | 14a49492036717 |
12 | 5745126500277 |
13 | 21c12ab26206c |
14 | c509b7089439 |
15 | 5bc0d689e357 |
hex | 2d867746dd7b |
50055550000507 has 2 divisors, whose sum is σ = 50055550000508. Its totient is φ = 50055550000506.
The previous prime is 50055550000487. The next prime is 50055550000597. The reversal of 50055550000507 is 70500005555005.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50055550000507 is a prime.
It is not a weakly prime, because it can be changed into another prime (50055550000597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25027775000253 + 25027775000254.
It is an arithmetic number, because the mean of its divisors is an integer number (25027775000254).
Almost surely, 250055550000507 is an apocalyptic number.
50055550000507 is a deficient number, since it is larger than the sum of its proper divisors (1).
50055550000507 is an equidigital number, since it uses as much as digits as its factorization.
50055550000507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 109375, while the sum is 37.
The spelling of 50055550000507 in words is "fifty trillion, fifty-five billion, five hundred fifty million, five hundred seven", and thus it is an aban number.
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