Base | Representation |
---|---|
bin | 100100011011001001101… |
… | …1110010101000001111011 |
3 | 122201120122111020020002011 |
4 | 1020312103132111001323 |
5 | 1124010003420213201 |
6 | 14351435314350351 |
7 | 1024452046156234 |
oct | 110662336250173 |
9 | 18646574206064 |
10 | 5006111101051 |
11 | 16600972311a5 |
12 | 68a27458b3b7 |
13 | 2a40c718c5a8 |
14 | 13442323608b |
15 | 8a348ea3151 |
hex | 48d9379507b |
5006111101051 has 2 divisors, whose sum is σ = 5006111101052. Its totient is φ = 5006111101050.
The previous prime is 5006111100997. The next prime is 5006111101087. The reversal of 5006111101051 is 1501011116005.
5006111101051 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5006111101051 - 233 = 4997521166459 is a prime.
It is a super-2 number, since 2×50061111010512 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5006111101151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2503055550525 + 2503055550526.
It is an arithmetic number, because the mean of its divisors is an integer number (2503055550526).
Almost surely, 25006111101051 is an apocalyptic number.
5006111101051 is a deficient number, since it is larger than the sum of its proper divisors (1).
5006111101051 is an equidigital number, since it uses as much as digits as its factorization.
5006111101051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 22.
Adding to 5006111101051 its reverse (1501011116005), we get a palindrome (6507122217056).
The spelling of 5006111101051 in words is "five trillion, six billion, one hundred eleven million, one hundred one thousand, fifty-one".
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