Base | Representation |
---|---|
bin | 101110101000101110… |
… | …110001000011110001 |
3 | 11210020211211112220022 |
4 | 232220232301003301 |
5 | 1310023310101423 |
6 | 35000535053225 |
7 | 3421626330032 |
oct | 565056610361 |
9 | 153224745808 |
10 | 50075472113 |
11 | 1a2673313a7 |
12 | 9856211215 |
13 | 49505a6194 |
14 | 25d0778a89 |
15 | 1481301dc8 |
hex | ba8bb10f1 |
50075472113 has 4 divisors (see below), whose sum is σ = 50233439220. Its totient is φ = 49917505008.
The previous prime is 50075472107. The next prime is 50075472247. The reversal of 50075472113 is 31127457005.
50075472113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1096470769 + 48979001344 = 33113^2 + 221312^2 .
It is a cyclic number.
It is not a de Polignac number, because 50075472113 - 26 = 50075472049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50075472313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78983078 + ... + 78983711.
It is an arithmetic number, because the mean of its divisors is an integer number (12558359805).
Almost surely, 250075472113 is an apocalyptic number.
It is an amenable number.
50075472113 is a deficient number, since it is larger than the sum of its proper divisors (157967107).
50075472113 is a wasteful number, since it uses less digits than its factorization.
50075472113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157967106.
The product of its (nonzero) digits is 29400, while the sum is 35.
The spelling of 50075472113 in words is "fifty billion, seventy-five million, four hundred seventy-two thousand, one hundred thirteen".
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