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50100111051 = 316700037017
BaseRepresentation
bin101110101010001100…
…110000011011001011
311210022120012100011120
4232222030300123023
51310101112023201
635003215130323
73422345626464
oct565214603313
9153276170146
1050100111051
111a27a22aa61
1298625139a3
134955721c33
1425d3b4dd6b
15148356c536
hexbaa3306cb

50100111051 has 4 divisors (see below), whose sum is σ = 66800148072. Its totient is φ = 33400074032.

The previous prime is 50100111049. The next prime is 50100111071. The reversal of 50100111051 is 15011100105.

50100111051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50100111051 - 21 = 50100111049 is a prime.

It is a super-2 number, since 2×501001110512 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 50100111051.

It is not an unprimeable number, because it can be changed into a prime (50100111071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8350018506 + ... + 8350018511.

It is an arithmetic number, because the mean of its divisors is an integer number (16700037018).

Almost surely, 250100111051 is an apocalyptic number.

50100111051 is a deficient number, since it is larger than the sum of its proper divisors (16700037021).

50100111051 is a wasteful number, since it uses less digits than its factorization.

50100111051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16700037020.

The product of its (nonzero) digits is 25, while the sum is 15.

Adding to 50100111051 its reverse (15011100105), we get a palindrome (65111211156).

The spelling of 50100111051 in words is "fifty billion, one hundred million, one hundred eleven thousand, fifty-one".

Divisors: 1 3 16700037017 50100111051