Base | Representation |
---|---|
bin | 101110101010001110… |
… | …000001011111111011 |
3 | 11210022120211012200211 |
4 | 232222032001133323 |
5 | 1310101203140011 |
6 | 35003230211551 |
7 | 3422351511604 |
oct | 565216013773 |
9 | 153276735624 |
10 | 50100443131 |
11 | 1a27a437502 |
12 | 9862653bb7 |
13 | 495580a12b |
14 | 25d3bd8dab |
15 | 14835d5b21 |
hex | baa3817fb |
50100443131 has 8 divisors (see below), whose sum is σ = 50159949840. Its totient is φ = 50040974592.
The previous prime is 50100443119. The next prime is 50100443143. The reversal of 50100443131 is 13134400105.
It is an interprime number because it is at equal distance from previous prime (50100443119) and next prime (50100443143).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 50100443131 - 213 = 50100434939 is a prime.
It is a super-2 number, since 2×501004431312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50100443111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3236496 + ... + 3251938.
It is an arithmetic number, because the mean of its divisors is an integer number (6269993730).
Almost surely, 250100443131 is an apocalyptic number.
50100443131 is a deficient number, since it is larger than the sum of its proper divisors (59506709).
50100443131 is a wasteful number, since it uses less digits than its factorization.
50100443131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19085.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 50100443131 its reverse (13134400105), we get a palindrome (63234843236).
The spelling of 50100443131 in words is "fifty billion, one hundred million, four hundred forty-three thousand, one hundred thirty-one".
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