Base | Representation |
---|---|
bin | 101110101010110110… |
… | …010110101010101001 |
3 | 11210100022201100101111 |
4 | 232222312112222221 |
5 | 1310111404444333 |
6 | 35004244550321 |
7 | 3422540414242 |
oct | 565266265251 |
9 | 153308640344 |
10 | 50111015593 |
11 | 1a2853a8781 |
12 | 98660b23a1 |
13 | 4957a6c422 |
14 | 25d538bcc9 |
15 | 14844c34cd |
hex | baad96aa9 |
50111015593 has 2 divisors, whose sum is σ = 50111015594. Its totient is φ = 50111015592.
The previous prime is 50111015579. The next prime is 50111015677. The reversal of 50111015593 is 39551011105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 29980229904 + 20130785689 = 173148^2 + 141883^2 .
It is a cyclic number.
It is not a de Polignac number, because 50111015593 - 29 = 50111015081 is a prime.
It is a super-2 number, since 2×501110155932 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (50111015533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25055507796 + 25055507797.
It is an arithmetic number, because the mean of its divisors is an integer number (25055507797).
Almost surely, 250111015593 is an apocalyptic number.
It is an amenable number.
50111015593 is a deficient number, since it is larger than the sum of its proper divisors (1).
50111015593 is an equidigital number, since it uses as much as digits as its factorization.
50111015593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3375, while the sum is 31.
Adding to 50111015593 its reverse (39551011105), we get a palindrome (89662026698).
The spelling of 50111015593 in words is "fifty billion, one hundred eleven million, fifteen thousand, five hundred ninety-three".
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